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Let’s return to considering a general state-space model. As before, let y∗1,…,y∗N be the data, x1,…,xN be the states. Then the likelihood function is L(θ)=P[y∗1:N|θ]=∑x1⋯∑xNN∏n=1P[y∗n|xn,θ]P[xn|xn−1,θ]. Thus, computation of the likelihood requires summing over all possible values of the unobserved process at each time point. This is very hard to do, in general. A general class of algorithms for evaluating this and other difficult integrals are the so-called Monte Carlo methods. Robert and Casella (2004) is an excellent technical reference on Monte Carlo techniques.
Simulation refers to the generation of random variables. The general problem of simulation is: given a probability distribution f, find a procedure that generates random draws from f. This is a very important problem in scientific computing and much thought and effort has gone into producing reliable simulators for many basic random variables. There are two basic ways of solving this problem:
This method works for discrete or continuous scalar random variables. Let f be the probability distribution function we seek to draw from (the target distribution) and F be the cumulative distribution function, i.e., F(x)=∫xf(x)dx. Let F−1(u)=inf be the inverse of F. A basic fact is that, if X\!\sim\!f, then F(X)\!\sim\!{\mathrm{Uniform}\left(0,1\right)}.
[Proof: {\mathbb{P}\left[{F(X)<u}\right]} = {\mathbb{P}\left[{X\,<\,F^{-1}(u)}\right]} = F(F^{-1}(u)) = u.]
This suggests that, if we can compute F^{-1}, we use the following algorithm to generate X\!\sim\!f:
The transformation method is very efficient in that we are guaranteed to obtain a valid X\!\sim\!f for every U\!\sim\!{\mathrm{Uniform}\left(0,1\right)} we generate. Sometimes, however, we cannot compute the inverse of the c.d.f., as required by the transformation method. Under such circumstances, the rejection method offers a less efficient, but more flexible, alternative. We’ll see how and why this method works.
Let’s suppose that we wish to simulate X\!\sim\!{\mathrm{Uniform}\left(D\right)}, where {D}\subset{U}. If we know how to generate Y\!\sim\!\mathrm{uniform}(U), then we can simply do so until {Y}\in{D}, at which point we take X=Y. Since for any A\subset{D}, {\mathbb{P}\left[{X\in A}\right]} = {\mathbb{P}\left[{Y\in A|Y\in D}\right]} = \frac{\mathrm{area}(A)}{\mathrm{area}(U)}/\frac{\mathrm{area}(D)}{\mathrm{area}(U)} = \frac{\mathrm{area}(A)}{\mathrm{area}(D)}, it follows that Y\!\sim\!\mathrm{uniform}(D). This is akin to throwing darts. If the darts are thrown in such a way as to be equally likely to land anywhere in U, then those that do land in D are equally likely to land anywhere in D.
Region D lies within region U. A random variable X is said to be uniformly distributed over a region D (X\!\sim\!\mathrm{uniform}(D)) if, for any {A}\subset{D}, {\mathbb{P}\left[{X\in{A}}\right]}=\mathrm{area}(A)/\mathrm{area}(D).
There is another seemingly trivial fact that underlies the rejection method and that Robert and Casella (2004) refer to as the fundamental theorem of simulation. Let h be an arbitary positive, integrable function, let D=\{(x,u): 0{\le}u{\le}h(x)\} be the planar region lying under the graph of h. Consider the random point (X,U)\!\sim\!\mathrm{uniform}(D). What is the marginal distribution of X? \int_0^{h(x)}\!{d{u}} = h(x)
So h is the probability density function for X!
This suggests the following rejection method for simulating an arbitrary random variable. Let f be the target distribution and g be another distribution function (from which it is easy to simulate) (see the diagram below). Let M be such that f(x) \le M\,g(x) for all x. The following procedure simulates X\!\sim\!f.
Diagram of the rejection method. M is chosen so that M\,g>f everywhere. We propose points by drawing them uniformly from the area under the graph of M\,g and accept them if they lie under the graph of f. The X-coordinate of the points are then distributed according to f.
Monte Carlo integration is a technique developed for evaluating integrals. First let’s look at the example of finding the area of a region, D\subset\mathbb{R}^n, with complicated boundaries. Solution: find some region U{\supset}D and throw darts at U. Count up the darts that land in D and reckon the area of D relative to U as the fraction of darts that land in D. Let X_k, k=1,2,\dots,N be N random darts thrown at U. \frac{\mathrm{area}(D)}{\mathrm{area}(U)} = \frac{\int_{D}\!{d{x}}}{\int_{U}\!{d{x}}} = \frac{\int_{U}\!I_D(x)\,{d{x}}}{\int_{U}\!{d{x}}} \approx \frac{\sum_{k=1}^{N}\!I_{D}(X_k)}{\sum_{k=1}^{N}\!1} = \frac{1}{N}\,\sum_{k=1}^{N}\!I_{D}(X_k)
In the above, the indicator function I_D is defined by I_D(x) = \begin{cases} 1 &x\in{D}\\ 0 &x\notin{D}\end{cases}
We’ve just shown that we can evaluate the integral of I_D over U. More generally, we can use this technique to approximate the integral of any integrable function, h, on U. \frac{\int_{U}\!h(x)\,{d{x}}}{\int_{U}\!{d{x}}} \approx \frac{1}{N}\,\sum_{k=1}^{N}\!h(X_k)
Here, we’re relying on the assumption that the darts fall uniformly on U. More generally still, we can compute an expectation with respect to an arbitrary distribution using Monte Carlo. This leads to what is known as the fundamental theorem of Monte Carlo integration: Let f(x) be the probability distribution function for x and let X_k, k=1,\dots,N be independent random variables, all distributed according to f. We speak of X_k as random samples from f. Let \overline{h_N} be the empirical average of h: \overline{h_N} = \frac{1}{N}\,\sum_{k=1}^{N}\!h(X_k). Then \overline{h_N} converges to \mathbb{E}[h(X)] as N\to\infty with probability 1. Thus \overline{h_N} = \frac{1}{N}\,\sum_{k=1}^{N}\!h(X_k) \approx {\mathbb{E}\left[{h(X)}\right]} = \int\!h(x)\,f(x)\,{d{x}}, for N sufficiently large.
Moreover, we can estimate the error in this approximation, because the empirical variance v_N = \frac{1}{N-1}\,\sum_{k=1}^{N}\!\left(h(X_k)-\overline{h_N}\right)^2 approximates the true variance, \mathrm{Var}[h(X)]=\mathbb{E}[(h(X)-\mathbb{E}[h(X)])^2]. This implies that the standard error on the approximation \overline{h_N}=\mathbb{E}[h(X)] is \sqrt{\frac{v_N}{N}} and that the error is approximately normally distributed: \overline{h_N}-\mathbb{E}[h(X)]\;\sim\;\mathrm{normal}\left(0,\sqrt{\frac{v_N}{N}}\right).
Sometimes it is difficult to sample directly from the distribution of X. In this case, we can often make use of importance sampling, in which we generate random samples from another distribution (easier to simulate) and make the appropriate correction.
Specifically, suppose we wish to compute {\mathbb{E}\left[{h(X)}\right]}, where X\sim{f}, but that it’s difficult or impossible to draw random samples from f. Suppose g is a probability distribution from which it’s relatively easy to draw samples and let Y_k\sim{g} for k=1\,\dots,N be i.i.d. random variables drawn from g. Notice that {\mathbb{E}\left[{h(X)}\right]} = \int\!h(x)\,f(x)\,{d{x}} = \int\!h(x)\,\frac{f(x)}{g(x)}\,g(x)\,{d{x}}. We can apply the Monte Carlo integration theorem to this integral to conclude that {\mathbb{E}\left[{h(X)}\right]} \approx \frac{1}{N}\,\sum_{k=1}^{N}\!h(Y_k)\,\frac{f(Y_k)}{g(Y_k)}.
Since {\mathbb{E}\left[{f(Y)/g(Y)}\right]}=1, we can replace the importance sampling rule above with another, which is slightly less accurate but more precise. Let w_k=f(Y_k)/g(Y_k) be the importance weights. Then we have {\mathbb{E}\left[{h(X)}\right]} \approx \overline{h} = \frac{\sum\!w_k\,h(Y_k)}{\sum\!w_k}. The Monte Carlo variance associated with this estimate is \frac{\sum\!w_k\,(h(Y_k)-\overline{h})^2}{\sum\!w_k}.
Obtaining accurate estimates requires some thought to the importance distribution g. Specifically, if the tails of g are lighter than those of f, the Monte Carlo variance will be inflated and the estimates can be unusable.
Robert, C. P., and G. Casella. 2004. Monte Carlo Statistical Methods. 2nd editions. Springer-Verlag.